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3.6x^2+2.3x-3.6=0
a = 3.6; b = 2.3; c = -3.6;
Δ = b2-4ac
Δ = 2.32-4·3.6·(-3.6)
Δ = 57.13
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2.3)-\sqrt{57.13}}{2*3.6}=\frac{-2.3-\sqrt{57.13}}{7.2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2.3)+\sqrt{57.13}}{2*3.6}=\frac{-2.3+\sqrt{57.13}}{7.2} $
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